I think I solved the paradox. It appears that the confusion emerges from analyzing the problem at too-high a level and sliding a few mistakes in such as believing that the time intervals are constant.
NOTE: OPEN IMAGES IN A NEW WINDOW TO VIEW THEM IN PARALLEL WITH THE EXPLANATION.
Here is the problem graphically:
At 1 you have your beginning situation. A is at 0 and B is at 8.
Say the speed of B is 2/sec and A is 8/sec.
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Now A has moved 8 units in a second to where B was before. B has moved only 2 units ahead.
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Now, B moves for a quarter of a second, so it goes 0.5 away, while A travels 2, to where B was before.
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B moves 0.125 while A moves 0.5 (in 1/16 of a second)
You may wonder why B is moving less and less each time. Well, for A to not have caught up to B yet, B can only move an amount of time in which A will not have had the chance to catch up with him.
What you see in the picture is that infinity is indeed involved. The problem is, not an infinity of time, but of divisions of space. To follow the conditions in the problem (ie, Achilles not catching up), we must make the time period of each motion smaller and smaller (this way Achilles can’t catch up). This means that eventually, at infinity time intervals, the two might converge. Thing is, add up all of these infinity of time intervals and you will get a constant time. What that means is that at a given, constant-valued time, A and B will converge after going through infinitely many intervals of time (yet still a finite sum).
Does the math support this answer? In fact, yes.
First, let’s look at the “naive” method of doing this, with which the paradox has a problem:
The position of B is as shown and A is as shown, both dependent on time t.
Setting them equal, we figure out that t=4/3 when they meet, and the distance from the origin is 32/8.
Now, the paradox says “that’s not true!”
Taking the insights I provided before with the first diagram (infinite time intervals, not infinite time), let’s see what series and calculus tell us:
We start by figuring out where B will end up. It begins at 8, so that is the first term. Next, we have to add an infinite geometric series. The first term is 2, so 2 is the numerator. The ratio is 1/4, so 1-1/4 is in the denominator. Solving, we get 32/3.
For A, it starts at 0 and its first geometric term is 8 with ratio 1/4, evaluating, we have 32/3.
This provides support for the idea that the problem is in the infinite time intervals, not actually infinite time.
The solution might be made more rigorous if I used dt instead of t, but the idea is there.
Yes, by the time Achilles reaches the turtle’s starting point the turtle is ahead, but much closer than initially. This keeps going and becomes smaller and smaller, until they converge. But note, too, that for Achilles to be always behind, the time period needs to shorten every time. The paradox arises by having the reader think that the time period of the movements is the same. It’s not. It’s a geometric series with a ratio < 1, so it converges to a constant. It has infinite time intervals, but converges to a constant.
I feel proud.